·If the normals of the parabola `y^2=4x` drawn at the end points of its latus rectum are tangents to the circle `(x-3)^2 (y+2)^2=r^2` , then the value of `r^2` is

If the normals of the parabola y^(2)=4x drawn at the end points of its latus rectum are tangents to the circle (x-3)^(2)+(y+2)^(2)=r^(2) , then the value of r^(4) is equal to

Find the equations of normal to the parabola y^(2)=4ax at the ends of the latus rectum.

The point of intersection of the normals to the parabola y^(2)=4x at the ends of its latus rectum is

The normal to y^(2)=4a(x-a) at the upper end of the latus rectum is

If the line 2x+3y=1 touches the parabola y^(2)=4ax then the length of latus rectum is

The end points of the latus rectum of the parabola x ^(2) + 5y =0 is

The end points of latus rectum of the parabola x ^(2) =4ay are

Slope of tangent to the circle (x-r)^(2)+y^(2)=r^(2) at the point (x.y) lying on the circle is

What is the area of the parabola y^(2) = x bounde by its latus rectum ?