A triangle `ABC` ofarea `5a^2` is inscribed in the parabola `y^2=4ax` such that vertex A lies at the veretex of parabola and `BC` is a focal chord. Then the length of focal chord is-

A triangle ABC of area Delta is inscribed in the parabola y^(2)=4ax such that the vertex A lies on the vertex of the parabola and the base BC is a focal chord.The difference of the distances of B and C from the axis of the parabola is (2Delta)/(a) (b) (4Delta)/(a^(2)) (c) (4Delta)/(a) (d) (2Delta)/(a^(2))

The triangle P Q R of area A is inscribed in the parabola y^2=4a x such that the vertex P lies at the vertex of the parabola and the base Q R is a focal chord. The modulus of the difference of the ordinates of the points Qa n dR is

The triangle PQR of area 'A' is inscribed in the parabola y^2=4ax such that the vertex P lies at the vertex pf the parabola and base QR is a focal chord.The modulus of the difference of the ordinates of the points Q and R is :

The triangle PQR of area 'A' is inscribed in the parabola y^2=4ax such that the vertex P lies at the vertex pf the parabola and base QR is a focal chord.The modulus of the difference of the ordinates of the points Q and R is :

The triangle PQR of area 'A' is inscribed in the parabola y^2=4ax such that the vertex P lies at the vertex pf the parabola and base QR is a focal chord.The modulus of the difference of the ordinates of the points Q and R is :

A triangle ABC is inscribed in the parabola y^(2)=4x such that A lies at the vertex of the parabola and BC is a focal chord of the parabola with one extremity at (9,6), the centroid of the triangle ABC lies at

A triangle ABC of area Delta is inserted in the parabola y^(2) =4ax such that A is the vertex and BC is a focal chord of the parabola then find the difference of the ordinates of B and C .