The normal at `P(8,8)` to the parabola `y^(2)=8x` cuts it again at `Q` then PQ

If the normal at P(18, 12) to the parabola y^(2)=8x cuts it again at Q, then the equation of the normal at point Q on the parabola y^(2)=8x is

Statement 1: Normal chord drawn at the point (8,8) of the parabola y^(2)=8x subtends a right angle at the vertex of the parabola.Statement 2: Every chord of the parabola y^(2)=4ax passing through the point (4a,0) subtends a right angle at the vertex of the parabola.

Consider the parabola y^(2)=8x, if the normal at a point P on the parabola meets it again at a point Q, then the least distance of Q from the tangent at the vertex of the parabola is

A tangent and a normal are drawn at the point P(8, 8) on the parabola y^(2)=8x which cuts the axis of the parabola at the points A and B respectively. If the centre of the circle through P, A and B is C, then the sum f sin(anglePCB) and cot(anglePCB) is equal to

The line x+y=6 is normal to the parabola y^(2)=8x at the point.

A normal drawn to the parabola y^2=4a x meets the curve again at Q such that the angle subtended by P Q at the vertex is 90^0dot Then the coordinates of P can be (a)(8a ,4sqrt(2)a) (b) (8a ,4a) (c)(2a ,-2sqrt(2)a) (d) (2a ,2sqrt(2)a)

The normal at a point P (36,36) on the parabola y^(2)=36x meets the parabola again at a point Q. Find the coordinates of Q.

The number of normal (s) to the parabola y^(2)=8x through (2,1) is