For the following cell reaction,
`Ag | Ag^(+) | AgCl | Cl^(-) | Cl_(2) , Pt`
`Delta G_(f)^(0) (AgCl) =-109 kJ//mol`
`Delta G_(f)^(0) (Cl ) = -129kJ//mol`
`Delta G_(f)^(0) (Ag^(+)) = 78 kJ//mol`
`E^@` of the cell is

For the following cell reaction {:(Ag|Ag^(+)|AgCl|Cl^(-)|Cl_(2),Pt),(DeltaG_(f)^(@)(AgCl)=-109kJ/mol,),(DeltaG_(f)^(@)(Cl^(-))=-129kJ/mol and),(DeltaG_(f)^(@)(Ag^(+))=78KJ/mol.E^(@)):} of the cell is

For the following reaction Ag_((aq))^(+)+Cl_((aq))^(-)rarrAgCl_((s)) Given : DeltaG_(f)^(@), AgCl=-"112.44 kJ/mol," DeltaG_(f)^(@) Cl^(-)=-"130 kJ/mol", DeltaG_(f)^(@)Ag^(+)="75 kJ/mol" Report your answer by rounding it upto nearest whole number. The K_(sp) of AgCl is nxx10^(-10) . The value of 'n'' is .

For the following reaction Ag_((aq))^(+)+Cl_((aq))^(-)rarrAgCl_((s)) Given : DeltaG_(f)^(@), AgCl=-"112.44 kJ/mol," DeltaG_(f)^(@) Cl^(-)=-"130 kJ/mol", DeltaG_(f)^(@)Ag^(+)="75 kJ/mol" Report your answer by rounding it upto nearest whole number. The K_(sp) of AgCl is nxx10^(-10) . The value of 'n'' is .

Calculate Delta_(r)G^(@) of the following reaction: Ag^(+)(aq)+Cl^(-)(aq)rarr AgCl(s) Given: Delta_(r)G^(@)(AgCl)=-"109kJ.mol"^(-1) , Delta_(r)G^(@)(Cl^(-))=-"129kJ.mol"^(-1), Delta_(r)G^(@)(Ag^(+))="77.kJ.mol"^(-1) . Represent the reaction in the form of E^(@) of the cell. Find log_(10)K_(sp)" of "AgCl .

Calculate Delta_(r)G^(c-) of the reaction : Ag^(o+)(aq)+Cl^(c-)(aq) rarr AgCl(s) Given :Delta_(f)G^(c-)._(AgCl)=-109kJ mol ^(-1) Delta_(f)G^(c-)_((Cl^(c-)))=-129k J mol ^(-1) Delta_(f)G^(c-)._((Ag^(o+)))=-77 kJ mol ^(-1)

Calculate Delta_(r)G^(c-) of the reaction : Ag^(o+)(aq)+Cl^(c-)(aq) rarr AgCl(s) Given :Delta_(f)G^(c-)._(AgCl)=-109kJ mol ^(-1) Delta_(f)G^(c-)_((Cl^(c-)))=-129k J mol ^(-1) Delta_(f)G^(c-)._((Ag^(o+)))=-77 kJ mol ^(-1)