`Delta ABC~DeltaDEC` such that ` ar(Delta ABC)=64 cm^(2) and ar (Delta DEF)=169 cm^(2)`. If `BC=4 cm`, find EF.

Delta ABC~ DeltaDEF such that ar (Delta ABC)= 36 cm^(2) and ar (Delta DEF) 49 cm^(2) . Then, the ratio of their corresponding sides is

Delta ABC - Delta DEF , Area of Delta ABC = 64 cm^(2) and area of Delta DEF = 121 cm^(2) . If EF = 15.4 cm , Find BC.

In DeltaABC ~ Delta DEF and ar (DeltaABC) = 100 cm^(2), ar (Delta DEF) = 196 cm^(2) and DE = 7 cm , then find AB.

If Delta ABC~Delta DEF such that 2AB=DE and BC=6 cm find EF.

If Delta ABC ~ Delta DEF such that area of Delta ABC " is " 9 cm^(2) and the area of Delta DEF " is " 16 cm^(2) and BC=2.1 cm. Find the length of EF.

Given two triangles ABC and DEF such that DeltaABC ~ Delta DEF . Also, ar(DeltaABC)= 25cm^(2), ar (Delta DEF)= 64cm^(2) and AB=5cm . Then length of side DE is

If triangle ABC~triangle DEF such that the area of triangle ABC is 9 cm^2 and the area of triangle DEF is 16 cm^2 . If BC=2.1 cm, find the length of EF.

Delta ABC ~ Delta EDF and area (Delta ABC) : Area (Delta DEF)=1:4 . If AB = 7cm, BC = 8 cm then DF=?

Delta ABC ~ Delta DEF and their areas are respectively 64 cm^(2) and 121 cm^(2) . If EF = 15.4 cm., then find BC.

Delta ABC ~ Delta DEF and their areas are respectively 64 cm^(2) and 121 cm^(2) . If EF = 15.4 cm., then find BC.