A wave is propagating in positive `x-`direction. A time `t=0` its snapshot is taken as shown. If the wave equation is `y=A sin(omegat-Kx+phi)`, then `phi` is

A wave propagates in a string in the positive x-direction with velocity v. The shape of the string at t=t_0 is given by f(x,t_0)=A sin ((x^2)/(a^2)) . Then the wave equation at any instant t is given by

A wave propagates in a string in the positive x-direction with velocity v. The shape of the string at t=t_0 is given by f(x,t_0)=A sin ((x^2)/(a^2)) . Then the wave equation at any instant t is given by

Two longitudinal waves propagating in the X and Y directions superimpose. The wave equations are as below Phi_(1)=A(omegat-kx) and Phi_(2)=Acos(omegat-ky) . Trajectory of the motion of a particle lying on the line y=x((2n+1)lamda)/(2) will be

Two longitudinal waves propagating in the X and Y directions superimpose. The wave equations are as below Phi_(1)=A(omegat-kx) and Phi_(2)=Acos(omegat-ky) . Trajectory of the motion of a particle lying on the line y=x((2n+1)lamda)/(2) will be

A wave is travelling along x-axis . The disturbance at x=0 and t=0 is A/2 and is increasing , where A is amplitude of the wave. If Y= sin (kx-omegat+phi) , then the initial phase is alpha pi . Find alpha

A wave is travelling along x-axis . The disturbance at x=0 and t=0 is A/2 and is increasing , where A is amplitude of the wave. If Y= sin (kx-omegat+phi) , then the initial phase is alpha pi . Find alpha

The wave progresses along the x-axis with time t. The instantaneous displacement from the mean position is given by y = a sin [(omegat-kx)+theta] . Then the dimensions are

Equation y=y_(0) sin (Kx+omega t) represents a wave :-

A progressive wave travelling along the positive x-direction is represented by y(x, t)=Asin (kx-omegat+phi) . Its snapshot at t = 0 is given in the figure. For this wave, the phase is: