The altitude from the vertex bisect the base in an isosceles triangle

In an isosceles triangle altitude from the vertex bisects the base.GIVEN: An isosceles triangle ABC such that AB=AC and an altitude AD from A on side BC. TO PROVE : D bisects BC i.e.BD=DC .Figure

In an isosceles triangle altitude from the vertex bisects the base. GIVEN : An isosceles triangle A B C such that A B=A C and an altitude A D from A on side B Cdot TO PROVE : D bisects B C i.e. B D=D Cdot Figure

In an isosceles triangle,the base angles are equal.The vertex angle is twice of either base In an isosceles triangles of the triangle?

The altitude drawn to the base of an isosceles triangle is 8cm and the perimeter is 32cm. Find the area of the triangle.

Prove that the bisector of the vertical angle of an isosceles triangle bisects the base at right angles.

Prove that the median from the vertex of an isosceles triangle is the bisector of the vertical angle.

In an Isoceless triangle altitude from the vertex bisects the base.

If the altitude from one vertex of a triangle bisects the opposite side; then the triangle is isosceless.

If the altitude from one vertex of a triangle bisects the opposite side, then the triangle is isosceles. GIVEN : A A B C such that the altitude A D from A on the opposite side B C bisects B C i.e., B D=D Cdot TO PROVE : A B=A C i.e. the triangle A B C is isosceles.

If the altitude from one vertex of a triangle bisects the opposite side, then the triangle is isosceles. GIVEN : A A B C such that the altitude A D from A on the opposite side B C bisects B C i.e., B D=D Cdot TO PROVE : A B=A C i.e. the triangle A B C is isosceles.