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tan(ilog((a+ib)/(a-ib)))=...

`tan(ilog((a+ib)/(a-ib)))=`

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Prove that tan(ilog_e((a-ib)/(a+ib)))=(2ab)/(a^2-b^2) (where a, b in R^+ )

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Prove that tan(ilog_e((a-ib)/(a+ib)))=(2ab)/(a^2-b^2) (where a, b in R^+ )

The value of (tan(i*log((a-ib)/(a+ib)))) is

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Prove that tan(i log_(e)((a-ib)/(a+ib)))=(2ab)/(a^(2)-b^(2)) (where a,b in R^(+))

tan (i log ((a + ib) / / a-ib))) =

tan [ i log ((a - ib)/(a + ib )) ] is equal to : a) ab b) (2 ab)/( a ^(2) - b ^(2)) c) (a ^(2) - b ^(2))/( 2 ab) d) (2 ab)/( a ^(2) + b ^(2))

If a and b are real and i=sqrt(-1) then sin[i ln((a+ib)/(a-ib))] is equal to

Write ((a+ib)/(a-ib))^(2)-((a-ib)/(a+ib))^(2) in the fom of x+iy