Solve `16x^4-1` =0. Find the value of x

If (4)^(2x- 1) - (16)^(x-1) = 384. find the value of x .

Solve 16x^(2)+4=0

Solve 16x^(2)+4=0

Solve 8x^(2)-16x=0 .

Solve 8x^(2)-16x=0 .

The first three terms in the expansion of (1+ax)^(n)(n ne 0) are 1,6x, and 16x^(2) . Then find the value of a and n.

If the polynomial 4x^(3)-16x^(2)+ax+7 is exactly divisible by x-1, then find the value of a. Hence factorise the polynomial.

If 2x-1 is a factor of 4x^(3) - 16x^(2) + 10x + k , find the value of k.

The first three terms in the expansion of (1+ax)^(n)(n!=0) are 1,6x and 16x^(2). Then find the value of a and n.

The first three terms in the expansion of (1+a x)^n(n!=0) are 1,6x and 16 x^2dot Then find the value of a and ndot