The displacement of a particle is given by ` x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t)`. The amplitude of particle is

The displacement of a particle varies according to relation x=4[cos pi t + sin pi t ] . The amplitude of the particle is

The displacement of a particle linear S.H.M. is given by x = 6 sin [3(pi)t + 5(pi) /6] meter. Find amplitude, frequency and the phase constant of the motion .

The displacement of a particle in S.H.M. is given by x=5["cos" pi t + "sin" pi t] where x is in metre. The amplitude of motion of the particle is given by

The displacement eqution of a particle is x=3 sin 2t + 4 cos 2t . The amplitude and maximum velocity will be respetively

The displacement of a particle performing SHM x= 3sin 2t+4 cos 2t . The amplitude and maximum velocity of a particle respectively are………….

The displacement of a SHM particle is y= 3 sin omega t+4 cos omega t then its amplitude will be……