To estimate `g` (from `g = 4 pi^(2)(L)/(T^(2))`), error in measurement of `L` is `+- 2%` and error in measurement of `Tis +- 3%` The error in estimated `g` will be

To estimate 'g' [from g=4pi^(2)((L)/(T^(2))) ], error in measurement of L is + 2% and error in measurement of T is + 3%. If the error estimated in 'g' is pm x % , then the value of x is

Error in the measurement of radius of a sphere is 2%. Then error in the measurement of surface area is ..............

What is the % error in measurement of T of a pendulum if maximum errors in measurements of length and ‘g’ are 2% and 4% respectively ?

In case of measurement of 'g' if error in measurement of length of pendulum is 2%, the percentage error in time period is 1 %. The maximum error in measurement of g is

In case of measurement of 'g' if error in measurement of length of pendulum is 2%, the percentage error in time period is 1 %. The maximum error in measurement of g is

The percentage error in determination fo g= 4pi^2(I)/(t^2), when I and t are measured with +- 1% and +- 2% errors is

The percentage error in the measurement of the voltage V is 3% and in the measurement of the current is 2%. The percentage error in the measurement of the resistance is

The percentage error in the measurement of the voltage V is 3% and in the measurement of the current is 2%. The percentage error in the measurement of the resistance is

Percentage error in the measurement of mass and speed are 2% and 3% respectively. The error in the measurement of kinetic energy obtained by measuring mass and speed will be