The line `3x-4y = 12` is a tangent to the ellipse with foci (-2, 3) and (-1, 0). Find the eccentricity of the ellipse.

Let x+2=0 is a tangent to an ellipse whose foci are (1,3) and (4,7) .If e is the eccentricity of the ellipse then e^(2)+(266)/(97) is equal to

Find the equation to the ellipse whose foci are (4, 0) and (-4, 0) and eccentricity is 1/3 .

Find the equation of the ellipse whose foci re (4,0) and (-4,0) eccentricity =1/3

Find the equation of the ellipse whose foci are (3,0) and(-3,0) and eccentricity 2/3.

The equation of the ellipse whose foci are (pm3,0) and eccentricity 3/4 is

Statement 1: If the line x+y=3 is a tangent to an ellipse with focie (4,3) and (6,y) at the point (1,2) then y=17 .Statement 2: Tangent and normal to the ellipse at any point bisect the angle subtended by the foci at that point.

Find the equation of the ellipse whose foci are (4,0) and (-4,0), eccentricity =1/3.

Consider the parabola y=x^(2)+7x+2 and the straight line y=3x-3 . What is equation of the ellipse having foci (+-2, 0) the eccentricity 1/4 ?

S (3, 4) and S^(') (9, 12) are the focii of an ellipse and the foot of the perpendicular from S to a tangent to the ellipse is (1, -4). Then the eccentricity of the ellipse is