If `y_1, y_2, y_3` be the ordinates of a vertices of the triangle inscribed in a parabola `y^2=4a x ,` then show that the area of the triangle is `1/(8a)|(y_1-y_2)(y_2-y_3)(y_3-y_1)|dot`

If y_(1),y_(2),y_(3) be the ordinates of a vertices of the triangle inscribed in a parabola y^(2)=4ax then show that the area of the triangle is (1)/(8a)|(y_(1)-y_(2))(y_(2)-y_(3))(y_(3)-y_(1))|

If y_(1),y_(2),andy_(3) are the ordinates of the vertices of a triangle inscribed in the parabola y^(2)=4ax , then its area is

If 2,4,8 are the ordinates of the vertices of a triangle inscribed in the parabola y^(2)=8x ,then area of triangle is

Prove that the area of the traingle inscribed in the parabola y^2=4ax is 1/(8a)(y_1~y_2)(y_2~y_3)(y_3~y_1) , where y_1,y_2,y_3 are the ordinates of the vertices.

Find the vertices and the area of the triangle whose sides are x=y, y=2x and y=3x+4 .

If (x_(1),y_(1)) & (x_(2),y_(2)) are the extremities of the focal chord of parabola y^(2)=4ax then y_(1)y_(2)=

If A(x_(1),y_(1)),B(x_(2),y_(2)),C(x_(3),y_(3)) are the vertices of the triangle then show that:'

The area of the triangle OAB with vertices O(0,0),A(x_(1),y_(1))B(x_(2),y_(2)) is