Given `M` is the mass suspended from a spring of force constant. `k`.The dimensional formula for `[M//k]^(1//2)` is same as that for

A block of mass m suspended from a spring of spring constant k . Find the amplitude of S.H.M.

A block of mass m suspended from a spring of spring constant k . Find the amplitude of S.H.M.

A block of mass m suspended from a spring of spring constant k . Find the amplitude of S.H.M.

A block of mass m is suspended by different springs of force constant shown in figure.

Two mass m_(1) and m_(2) are suspended from a massless spring of force constant k. When the masses are in equilibrium, m_(1) is removed without disturbing the system. Find the angular frequency and amplitude of oscillations.

The frequency of oscillation of a mass m suspended from a spring having force constant k is given by f = Cm^(x)k^(g) , where C is a dimensionless quantity. The value of x and y

A mass m is suspended from a spring of force constant k. The period of oscillation is T_0 The spring is cut into 4 equal parts: The same mass m is suspended from one of the parts. What is the new period?

The frequency of vibration v of mass m suspended from a spring of spring constant k is given by f=cm^(x)k^(y) where c is a dimensional constant. The volumes of x and y are :

The frequency f of vibrations of a mass m suspended from a spring of spring constant k is given by f = Cm^(x) k^(y) , where C is a dimensionnless constant. The values of x and y are, respectively,