Atomicity of oleum `(H_(2)S_(2)O_(7))` is

Write the structure of oleum (H_(2)S_(2)O_(7))

Oxidation number of sulphur in oleum (H_(2)S_(2)O_(7)) is

Passage - VI : Industrially sulphuric acid is produced by the following steps: Stage I : S+O_(2) overset(Delta)to SO_(2) Stage II : 2SO_(2) +O_(2) overset(V_(2)O_(5))to 2SO_(3) Stage III : SO_(3)+H_(2)O to H_(2)SO_(4) Since the reaction between SO_(3) and H_(2)O is violent, SO_(3) is passed into 98% H_(2)SO_(4) to produce oleum (H_(2)S_(2)O_(7)) Pure H_(2)SO_(4) does not react with metal because -

The oxidation state of sulphur in H_(2)S_(2)O_(7) is

Oxidation number of S in H_(2)S_(2)O_(7) is -

The correct oxidation state of sulphur atoms in H_(2)S_(2)O_(3) is / are

Drawn the structure of the following (i) H_(2)S_(2)O_(7) (ii) XeF_(6)

Drawn the structure of the following (i) H_(2)S_(2)O_(7) (ii) XeF_(6)

The number of gm atoms of oxygen present in 0.2 mole of H_(2)S_(2)O_(8) is.