For the reaction `2N_(2)O_(5 )rarrNO_(2)+O_(2)` rate of reaction is :

For the reaction 2N_(2)O_(5) rarr 4NO_(2)+O_(2) rate of reaction and rate constant are 1.02 xx 10^(-4) and 3.4 xx 10^(-5) sec^(-1) respectively. The concentration of N_(2)O_(5) at that time will be

For the reaction : 2N_(2)O_(5) rarr 4NO_(2) +O_(2) , the rate of reaction in terms of O_(2) is d[O_(2)] /dt. In terms of N_(2)O_(5) , it will be :

For the reaction : 2N_(2)O_(5) rarr 4NO_(2) +O_(2) , the rate of reaction in terms of O_(2) is d[O_(2)] /dt. In terms of N_(2)O_(5) , it will be :

For the reaction 2N_(2)O_(5)rarr 4NO_(2)+O_(2) , if rate formation of O_(2) is 16 g//hr , then rate of decomposition of N_(2)O_(5) and rate of formation of NO_(2) respectively is:

For the reaction, 2N_2O_5rarr4NO_2+O_2 , rate of reaction in terms of O_2 is d[ O_2 ]/dt . In term of N_2O_5 will be:

For the reaction 2N_(2)O_(5)rarr4NO_(2)+O_(2) the rate equation can be express as (d[N_(2)O_(5)])/(dt)=k[N_(2)O_(5) and (d[NO_(2)])/(dt)=k'[N_(2)O_(5)] k and k' are related as

For the reaction : 2N_2O_5 rarr 4NO_2+O_2 the rate of reaction measured as (Delta [NO_2])/(Delta t) was found to be 1 xx 10^-3 mol L^(-1) s^(-1) . Calculate rate of reaction expressed in terms of N_2O_5 .

For the reaction : 2N_2O_5 rarr 4NO_2+O_2 the rate of reaction measured as (Delta[NO_2])/(Deltat) was found to be 4 xx 10^(-3)" mol L"^(-1) is s^(-1) . Calculate the rate of reaction, expressed in terms of N_2O_5