If `x+y=k` is normal to `y^2=12 x ,` then `k` is 3 (b) 9 (c) `-9` (d) `-3`

If x+y=k is normal to y^(2)=4x ,then the value of k is

If x+y=k is a normal to the parabola y^(2)=12x , then the value of k is-

If x+y=k is a normal to the parabola y^(2)=12x then it touches the parabola y^(2)=px then

If x+y=k is a normal to the parabola y^(2)=12x, then it touches the parabola y^(2)=px then |P| =

If (2k-1, k) is a solution of the equation 10 x-9y=12 , then k= (a) 1 (b) 2 (c) 3 (d) 4

The normal to the parabola y^2 = 4ax from the point (5a, 2a) are (A) y=x-3a (B) y=-2x+12a (C) y=-3x+33a (D) y=x+3a

If (x+y)^3- (x-y)^3-6y (x^2-y^2)= k y^3, then k= (a)1 (b) 2 (c) 4 (d) 8

If the two parabolas y^2 = 4x and y^2 = (x-k) have a common normal other than x-axis, then value of k can be (A) 1 (B) 2 (C) 3 (D) 4