The velocity of particle is `v=v_(0)+"gt"+ft^(2)`. If its position is `x=0` at `t=0` then its displacement after unit time `(t=1)` is

The velocity of particle is v= v_0 +gt+ ft^(2) if its position is x =0 at t=0, then its displacement after unit time is:

The velocity of a particle is v=v_(0)+gt+ft^(2) .If its position is x=0 at t=0, then its displacement after 1s is

The velocity of a particle is v = v_(0) + gt + ft^(2) . If its position is x=0 at t= 0 , then its displacement after unit time ( t = 1 ) is

The velocity of a particle is v = v_0 + g t + ft^2 . If its position is x = 0 at t = 0 , then its displacement after unit time (t = 1) is.

The velocity of a particle is u=v_0 + gt + ft^2 . If its position is x = 0 at t=0, Then it's displacement after time (t = 1 ) is

The velocity of a particle is v=v_(0)+g t+Ft^(2) . Its position is x=0 at t=0, then its displacement after time (t=1) is :

"The velocity of a particle is v=v_0+(gt)+ft^2 . If its position x=0 at t=0 , then its displacement afler time (t= 1) is

The velocity of a particle is given by v=u_(0) + g t+ 1/2 at^(2) . If its position is x =0 at t=0 , then what is its displacement after t=1 s ?

If velocity of a moving particle in is v= a + g t + ft^2 (a,g,f are constants). At t=0 body is at origin. Find displacement after t=1s.