The equilibrium constant of the reaction,
`SO_(3)(g) hArr SO_(2)(g)+1//2 O_(2)(g)`
is `0.15` at `900 K`. Calculate the equilibrium constant for
`2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)`

The equilibrium constant for the reaction 2SO_(3(g))hArr2SO_(2(g))+O_(2(g)) is 0.15 at 900 K. Calculate the equilibrium constant for the reaction 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) at the same temperature.

The equilibrium constant for the reaction 2SO_(3(g))hArr2SO_(2(g))+O_(2(g)) is 0.15 at 900 K. Calculate the equilibrium constant for the reaction 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) at the same temperature.

The equilibrium constant for the reaction 2SO_(3(g))hArr2SO_(2(g))+O_(2(g)) is 0.15 at 900 K. Calculate the equilibrium constant for the reaction 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) at the same temperature.

The equilibrium constant for the reaction 2SO_(3(g))hArr2SO_(2(g))+O_(2(g)) is 0.15 at 900 K. Calculate the equilibrium constant for the reaction 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) at the same temperature.

The equilibrium constant for the reaction: SO_3(g) hArr SO_2(g) +1/2O_2(g) is 0.18 at 900 K. What will be the equilibrium constant for the reaction: 2SO_2(g) + O_2(g) hArr SO_3(g)

The equilibrium constant of the reaction , SO_(3(g))hArrSO_(2(g))+(1)/(2)O_(2(g)) , is 0.20 "mole"^(1//2)litre^(-1//2) at 1000 K . Calculate equilibrium constant for 2SO_(2(g))+O_(2(g))hArr2SO_(3(g))

The equilibrium constant for the reaction 2SO_(2)(g)+O_(2)(g)hArr 2SO_(3)(g) is 256 at 1000 K. The equilibrium constant for the reaction : SO_(3)(g)hArr SO_(2)(g)+1//2 O_(2)(g) is :

The equilibrium constant of the reaction, SO_(2)(g) + 1/2 O_(2)(g) hArr 2SO_(3)(g) is 5 xx 10^(-2)atm . The equilibrium constant of the reaction, 2SO_(3)(g) hArr 2SO_(2)(g) + O_(2)(g)