A ground to ground projectile is at point A at `t = (T)/(3)`, is at point B at `t = (5T)/(6)` and reaches the ground at `t = T`. The difference in heights between points A and B is

A particle is projected vertically from the ground takes time t_(1)=1 s upto point A , t_(2)=3 s from point A to B , and time t_(3)=4 s from point B to highest point. Find the height of the middle point of A and B from the ground.

A particle is projected vertically from the ground takes time t_(1)=1 s upto point A , t_(2)=3 s from point A to B , and time t_(3)=4 s from point B to highest point. Find the height of the middle point of A and B from the ground.

For ground to ground projectile, time take by a particle to ge point O to point C is T_(1) and during the same motion time taken by the particle to ge from A to B is T_(2) then height 'h' is :

For ground to ground projectile, time take by a particle to ge point O to point C is T_(1) and during the same motion time taken by the particle to ge from A to B is T_(2) then height 'h' is :

A stone projected vertically up from the ground reaches a height y in its path at t_(1) seconds and after further t_(2) seconds reaches the ground. The height y is equal to

A particle is projected vertically upwards from a point A on the ground. It takes t_(1) time to reach a point B but it still continues to move up. If it takes further t_(2) time to reach the ground from point B then height of point B from the ground is :-