If `cot^3alpha+cot^2alpha+cotalpha=1` then (a) `cos2alpha.tanalpha=-1` (b)`cos2alpha.tanalpha=1` (c) `cos2alpha-tan2alpha=1` (d)`cos2alpha-tan2alpha=-1`

1/(tan3alpha-tanalpha)-1/(cot3alpha-cotalpha)=cot2alpha

tan2alpha-tanalpha(1+sec2alpha)=

For alpha=pi/7 which of the following hold(s) good? (a) tanalphatan2alphatan3alpha=tan3alpha-tan2alpha-tanalpha (b) cos e calpha=cos e c2alpha+cos e c4alpha (c) cosalpha-cos2alpha+cos3alpha=1/2 (d) 8cosalphacos2alphacos4alpha=1

For alpha=pi/7 which of the following hold(s) good? (a) tanalphatan2alphatan3alpha=tan3alpha-tan2alpha-tanalpha (b)cos e calpha=cos e c2alpha+cos e c4alpha (c)cosalpha-cos2alpha+cos3alpha=1/2 (d)8cosalphacos2alphacos4alpha=1

If cos^2alpha=sin^3alpha then show that tan^6alpha-tan^2alpha=1

(x tan alpha+y cot alpha)(x cot alpha+y tan alpha)-4xy cos^(2)2 alpha=

If tan alpha+cotalpha=2 , then tan^(20)alpha+cot^(20)alpha =

(tan alpha sec^(2)alpha+cot alpha cos ec^(2)alpha)-(tan alpha+cot alpha)=2cos ec2 alpha[sec^(2)alpha+cos ec^(2)alpha-3]

sin^(2) alpha * tan alpha + cos^(2) alpha * cot alpha + 2 sin alpha cos alpha =

If cot alpha cot beta=2 show that (cos(alpha+beta))/(cos(alpha-beta))=1/3