At what point on the parabola `y^2=4x` the normal makes equal angle with the axes? (A) `(4,4)` (B) `(9,6)` (C) `(4,-4)` (D) `(1,+-2)`

The points on the curve 9y^2=x^3 , where the normal to the curve makes equal intercepts with the axes are (A) (4,+-8/3) (B) (4,(-8)/3) (C) (4,+-3/8) (D) (+-4,3/8)

The point on the curve y^2=x where tangent makes 45o angle with x-axis is (1//2,\ 1//4) (b) (1//4,\ 1//2) (c) (4,\ 2) (d) (1,\ 1)

The point on the curve 9y^2=x^3 , where the normal to the curve makes equal intercepts with the axes is (4,\ +-8//3) (b) (-4,\ 8//3) (c) (-4,\ -8//3) (d) (8//3,\ 4)

The point on the curve y^(2) = 4ax at which the normal makes equal intercepts on the coordinate axes is

A normal is drawn at a point " (x_(1),y_(1)) " of the parabola " y^(2) - 16x " and this normal makes equal angle with both "x" and "y" axes,Then point " (x_(1),y_(1)) " is (a) " (4,-4) ," (b) " (2,-8) " (c) " (4,-8) " (d) " (1,-4) "

The normal to parabola y^(2) =4ax from the point (5a, -2a) are

The normals to the parabola y^(2)=4ax from the point (5a,2a) is/are

If the tangents drawn from the point (0,2) to the parabola y2=4ax are inclined at angle-t, then the value of 'a' is (A) 2 (C) 1 1.4 (B) -2 (D) none of these

If the tangents to the parabola y^(2)=4ax make complementary angles with the axis of the parabola then t_(1),t_(2)=