How much faster than its present speed should the. earth (radius `6.37 xx 10^(6)m`) rotate so that the bodies lying on the equator may fly off into space? (At equator, `g=9.78m//s^(-2)`)

How many times faster than the present speed should the earth move to rotate about it’s axis, so that the apparent weight of the bodies on the equator becomes Zero.

The angular velocity of earth at present is omega . What should be its angular velocity so that the body lying at the equator flies off

How mcuh faster than its present rate should the earth rotate about its axis so that the weight of a body at the equator becomes zero? Also calculate the new length of the day. (c ) What would happen if rotation becomes faster ?

What is the weight of a body of mass 20kg at the equator ?(g=9.78 m/s^2)

How many times faster than its present speed the earth should rotate so that the apparent weight of an object at equator becomes zero ? Given radius of the earth = 6.37 xx 10^(6) m . What would be the duration of the day in that case ?

Calculate the capacitance of earth, taking its radius to be 6.37 xx 10^(6)m

How much faster than it's normal rate should the earth rotate about it's axis so that the weight of the body at the equator becomes zero (R=6.4xx10^(6)m,g=9.8m//s^(2)) (in times)