A particle moves under the law `s=t^(3)-4t^(2)-5t.` If its acceleration is `4" units/sec^(2),` then its velocity is

A particle moves under the law s=t^(3)-4t^(2)-5t. If its acceleration is 4" units/sec"^(2) , then its displacement is

If S=4 t^(3)-3t^(2)+2 , then acceleration is 42 "units" // sec ^(2) at the time t=

If the displacement of a particle is given by s=2t^(3)-5t^(2)+4t-3 , then its acceleration is 14" ft/sec"^(2) after to,e

If the displacement of a particle is given by s=2t^(3)-5t^(2)+4t-3 , then its velocity when acceleration is 14" ft/sec"^(2) , is

A particle moves according to law s=t^3-3t^2+3t+12 . The velocity when the acceleration is zero is

If the displacement of a particle is given by s=2t^(3)-5t^(2)+4t-3 , then its displacement when acceleration is 14" ft/sec"^(2) , is

The motion of a particle is described as S =2-3t+4t^(3) what is the acceleration of the paricle at the point where its velocity is zero ?

The displacement s of a moving particle at a time t is given by s=5+20t-2t^(2) . Find its acceleration when the velocity is zero.

A particle moves according to the law x=t^(3)-6t^(2)+9t+5 . The displacement of the particle at the time when its acceleration is zero, is