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0.001 mol of Co(NH(3))(5)(NO(3))(SO(4)) ...

`0.001` mol of `Co(NH_(3))_(5)(NO_(3))(SO_(4))` was passed through a cation exchanger and the acid coming out of it required 20 ml of 0.1 M NaOH for neutralisation. Hence, the complex is

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0.001 mol of Cr(NH_(3))_(5)(NO_(3))(SO_(4)) was passed through a cation exchanger the acid coming out of it reguired 20mL of 0.1M NaoH for netralisation Hence the complex is [Cr(NH_(3))_(5)SO_(4)]NO_(3) (b) [Cr(NH_(3))_(5)NO_(3)]SO_(4) (c ) [Cr(NH_(3))_(5)](SO_(4))(NO_(3) (d) [Co(NH_(3))_(5)Br]SO_(4) .

0.001 mol of Cr(NH_(3))_(5)(NO_(3))(SO_(4)) was passed through a cation exchanger the acid coming out of it reguired 20mL of 0.1M NaoH for netralisation Hence the complex is [Cr(NH_(3))_(5)SO_(4)]NO_(3) (b) [Cr(NH_(3))_(5)NO_(3)]SO_(4) (c ) [Cr(NH_(3))_(5)(SO_(4))](NO_(3) (d) [Co(NH_(3))_(5)Br]SO_(4) .

A solution containing 0.319 g of complex CrCl_(3).6H_(2)O was passed through cation exchanger and the solution given out was neutralised by 28.5 ml of 0.125 M NaOH. The correct formula of the complex will be: [ molecular weight of complex =266.5]

A solution containing 0.319 g of complex CrCl_(3).6H_(2)O was passed through cation exchanger and the solution given out was neutralised by 28.5 ml of 0.125 m NaOH. The correct formula of the complex will be: [ molecular weight of complex =266.5]