The graph of the linear equation `2x-y=4` cuts x-axix at (a) `(2,0)` (b) `(-2,0)` (c) `(0,-4)` (d) `(0,4)`

The graph of the linear equation 2x-y=4 cuts x-axis at

The graph of the linear equation 2x-y=4 cuts the x-axis at

The graph of the linear equation 2x-y=4 cuts x -axix at (a,0)(b)(-2,0)(c)(0,-4)(d)(0,4)

Draw the graph for the equation : 2y+4x+2=0

The graph of y=x^(3)-4x cuts x-axis at (-2,0), (0,0) and (2,0). The zeroes of x^(3)-4x are

x=2, y=−1 is a solution of the linear equation (a) x+2y=0 (b) x+2y=4 (c) 2x+y=0 (d) 2x+y=5

The system of linear equations x + y + z = 0 (2x)/(a) + (3y)/(b) + (4z)/(c ) = 0 (x)/(a) + (y)/(b) + (z)/(c ) = 0 has non trivia solution then

The system of linear equations x + y + z = 0 (2x)/(a) + (3y)/(b) + (4z)/(c ) = 0 (x)/(a) + (y)/(b) + (z)/(c ) = 0 has non trivia solution then

Solve graphically the system of linear equations 4x-5y+16=0 and 2x+y-6=0.

The equation of the normal to the curve y=x(2-x) at the point (2,\ 0) is x-2y=2 (b) x-2y+2=0 (c) 2x+y=4 (d) 2x+y-4=0