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A wooden bookshelf has external dimens...

A wooden bookshelf has external dimensions as follows: Height = 10 cm, Depth = 25cm, Breadth = 85 cm (See in Figure). The thickness of the plank is 5 cm everywhere. The external faces are to be polished and the inner faces are to be painted. If the rate of polishing is 20 paise per `c m^2` and the rate of painting is 10 paise per `c m^2` . Find the total expenses required for polishing and painting the surface of the bookshelf.

Text Solution

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Since the bookshelf is cuboidal in shape and opened at the front with three shelves of the same dimensions, the area to be polished will be 5 surfaces of cuboidal bookshelf and the front border with plank’s thickness.
The area to be painted will be 3 shelves of the bookshelf with internal dimensions and the area of each shelf will be 5 surfaces of the cuboidal shelf.
We can calculate the total cost of polishing and painting by multiplying the rate and their respective area.
The Volume of a cuboid of length l, breadth b, and height h, is = `l xx b xx h` External measures of the bookshelf is,
Breadth, B = `85` cm
Depth, D = 25 cm
Height, `H = 110 cm`
The thickness of the plank, `t = 5 cm`
Internal measures of the bookshelf is,
The breadth of each shelf, b = B - 2t
`b = 85 cm - 2 xx 5 cm = 75 cm`
Depth of each shelf, `d = D - t`
` d = 25 cm - 5 cm = 20 cm`
Height of each shelf, `h = H - 4t`
`= (110 cm - 4 xx 5 cm) div 3`
`= 90/3 cm = 30 cm`
Now, Surface area to be polished = External 5 surfaces of the bookshelf + border of the shelf
`= 2(B + H) D + BH + 2Ht + 4bt`
`= [2 xx (85 cm + 110 cm) xx 25 cm] + (85 cm xx 110 cm) + (2 xx 110 cm xx 5 cm) + (4 xx 75 cm xx 5 cm)`
`= 9750 cm^2 + 9350 cm^2 + 1100 cm^2 + 1500 cm^2`
`= 21700 cm^2`
Cost of polishing at the rate of 20 paise per `cm^2 = 21700 cm^2 xx (₹ 20/100) / cm^2 = ₹ 4340`
Surface area to be painted = Internal 5 surfaces of 3 shelves
= 3 [2(b + h)d + bh]
`= 3 [2 xx (75 cm + 30 cm) xx 20 cm + (75 cm xx 30 cm)]`
`= 3 [4200cm^2 + 2250 cm^2]` `= 3 xx 6450 cm^2`
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