A ball is thrown with speed `u` at an angle `theta` with horizontally. After how much time it will move perpendicular to the initial direction of motion.

A particle is thrown with a speed u at an angle theta with horizontal. After how much time the velocity of particle will be perpendicular to the initial motion of direction

A ball is thrown with velocity 8 ms^(-1) making an angle 60° with the horizontal. Its velocity will be perpendicular to the direction of initial velocity of projection after a time of (g =10ms^(-2) )

A ball is thrown with velocity 8 ms^(-1) making an angle 60° with the horizontal. Its velocity will be perpendicular to the direction of initial velocity of projection after a time of (g =10ms^(-2) )

A ball is thrown with velocity 8 ms^(-1) making an angle 60^(@) with the horizontal.Its velocity will be perpendicular to the direction of initial velocity of projection after a time of

A particle is projected with a speed u at an angle theta with the horizontal. What will be the speed of the particle when direction of motion of particle is at an angle alpha with the horizontal?

A particle is thrown with speed u at an angle alpha with horizontal from the ground. After how much time, the velocity of particle will make an angle beta with horizontal.

A ball is thrown with a speed u, at an angle theta with the horizontal. At the highest point of its motion, the strength of gravity is somehow doubled. Taking this change into account, the total time of flight of the projectile is

A ball is thrown with a speed u, at an angle theta with the horizontal. At the highest point of its motion, the strength of gravity is somehow doubled. Taking this change into account, the total time of flight of the projectile is