A ray of light travels along a line `y=4` and strikes the surface of curves `y^2=4(x+y)dot` Then the equations of the line along which of reflected ray travels is `x=0` (b) `x=2` (c) `x+y` (d) `2x+y=4`

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

A ray of light travels along the line 2x-3y+5=0 and strikes a plane mirror lying along the line x+y=2 . The equation of the straight line containing the reflected ray is

A ray of light is sent along the line x-2y-3=0 on reaching the line 3x-2y-5=0 the ray is reflected from it, then the equation of the line containing the reflected ray is

An incident ray is coming along the straight line y=4 and it strikes the parabola y^(2)=4x, then equation of the reflected ray is

A ray of light, coming along the straight line 2x+3y=6 , strikes at x -axis and reflects, then the equation of the reflected ray

A ray of light is sent along a line x-2y-3=0 .Upon reaching the line 3x-2y-5=0 the ray is reflected.Find the equation of the line containing the reflected ray.

A ray of light is sent along the line x-2y-3=0 upon reaching the line 3x-2y-5=0, the ray is reflected from it. Find the equation of the line containing the reflected ray.

A ray of light is sent along the line x-2y+5 = 0 upon reaching the line 3x- 2y + 7 = 0 the ray is reflected from it . Find the equation of the containing the reflected ray .

A ray of light travelling along the line x+y=1 is incident on the x-axis and after refraction it enters the other side of the x-axis by turning 30^0 away from the x-axis. The equation of the line along which the refracted ray travels is

The equation of the normal to the curve y=x(2-x) at the point (2,\ 0) is x-2y=2 (b) x-2y+2=0 (c) 2x+y=4 (d) 2x+y-4=0