Home
Class 11
CHEMISTRY
Li' forms a body centered cubic lattice....

Li' forms a body centered cubic lattice. If the lattice constant is `3.5xx10^(-10)m` and the experimental density is `5.30xx10^(3) kgm^(-3)`, calculate the percentage occupancy of Li metal.

Promotional Banner

Similar Questions

Explore conceptually related problems

Li forms a body-centred cubic lattice. If the edge of the cube is 3.5 xx 10^(-10)m and the density is 5.3 xx 10^(2) kg m^(-3) , calculate the percentage occupancy of Li metal.

Li forms a body-centred cubic lattice. If the edge of the cube is 3.5 xx 10^(-10)m and the density is 5.3 xx 10^(2) kg m^(-3) , calculate the percentage occupancy of Li metal.

Li forms a body-centred cubic lattice. If the edge of the cube is 3.5 xx 10^(-10)m and the density is 5.3 xx 10^(2) kg m^(-3) , calculate the percentage occupancy of Li metal.

An element X (At. Wt. =24) forms FCC lattice. If the edge length of lattice is 4 xx 10^(-8) cm and the observed density is 2.4 xx 10^(3 kg//m^(3) . Then the percentage occupancy of lattice point by element X is : (N_(A) = 6 x 10^(23))

An element X (At. Wt. =224) forms FCC lattice. If the edge length of lattice is 4 xx 10^(-8) cm and the observed density is 2.4 xx 10^(3 kg//m^(3) . Then the percentage occupancy of lattice point by element X is : (N_(A) = 6 x 10^(23))

An element X (At. Wt. =24) forms FCC lattice. If the edge length of lattice is 4 xx 10^(-8) cm and the observed density is 2.4 xx 10^(3 )kg//m^(3) . Then the percentage occupancy of lattice point by element X is : (N_(A) = 6 x 10^(23))

Silver crystallises in face centered cubic lattice. If edge length of the unit cell is 4.07xx10^(-8) cm and density of silver is 10.48 g cm^(-3) determine the relative atomic mass of silver.