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If alpha is the fraction of HI dissociat...

If `alpha` is the fraction of HI dissociated at equilibrium in the reaction, `2HI(g)hArrH_2(g)+I_2(g)` starting with the 2 moles of HI. Then the total number of moles of reactants and products at equilibrium are

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For the reaction, H_(2) + I_(2)hArr 2HI, K = 47.6 . If the initial number of moles of each reactant and product is 1 mole then at equilibrium

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