`cos(pi/7)cos((2pi)/7)cos((4pi)/7)=`

Prove that : cos(pi/7)cos((2pi)/7) cos((3pi)/7)=1/8

Show that cos(pi/7)cos((2pi)/7)cos((3pi)/7)=1/8

The value of cos(pi/7)+cos((2pi)/7)+cos((3pi)/7)+cos((4pi)/7)+cos((5pi)/7) +cos((6pi)/7)+cos((7pi)/7) is

cos(pi/7)+cos((2pi)/7)+cos((3pi)/7)+cos((4pi)/7)+cos((5pi)/7)+cos((6pi)/7)=

The value of cos(pi/7)+cos((2pi)/7)+cos((3pi)/7)+cos((4pi)/7)+cos((5pi)/7)+cos((6pi)/7)+cos((7pi)/7) is 1 (b) -1 (c) 0 (d) none of these

The value of cos(pi/7)+cos((2pi)/7)+cos((3pi)/7)+cos((4pi)/7)+cos((5pi)/7)+cos((6pi)/7)+cos((7pi)/7) is 1 (b) -1 (c) 0 (d) none of these

Prove that cos((2pi)/7)cos((4pi)/7)cos((8pi)/7)=1/8

Prove that: cos(pi)/(7)cos(2 pi)/(7)cos(4 pi)/(7)=-(1)/(8)

The value of cos((2pi)/7)cos((4pi)/7)cos((6pi)/7) is

The value of cos((2pi)/7)cos((4pi)/7)cos((6pi)/7) is a. -1//2 b. \ 1//2 c. \ 1//4 d. 1//8