If `(5+2sqrt6)^(x^2-3) +(5-2sqrt6)^(x^2-3)=10` then x= (i)`+-2,+-sqrt2` (ii) `+-1,+-sqrt2` (iii) `+-4,+-sqrt2` (iv) `+-sqrt5,+-sqrt2`

If (5+2sqrt(6))^(x^(2)-3)+(5-2sqrt(6))^(x^(2)-3)=10 then x=(i)+-2,+-sqrt(2)(ii+-1,+-sqrt(2) (iii) +-4,+-sqrt(2)(iv)+-sqrt(5),+-sqrt(2)

If (5+2sqrt(6))^(x^2-3)+(5-2sqrt(6))^(x^2-3)=10, then x=----------

Solve : (5+2sqrt6)^(x^(2)-3) +(5-2sqrt6)^(x^(2)-3) = 10

Simplify: (i) (2 sqrt(2) + 3 sqrt(3)) (2 sqrt(2) - 3 sqrt(3)) (ii) (2 sqrt(8) - 3 sqrt(2))^(2) (iii) (sqrt(7) + sqrt(6))^(2) (iv) (6 - sqrt(2))(2 + sqrt(3))

Choose the incorrect relation(s) from the following : (I ) sqrt(6) + sqrt(2) = sqrt(5) + sqrt(3) (ii) sqrt(6) + sqrt( 2) lt sqrt(5) + sqrt (3) (iii) sqrt(6) + sqrt(2) gt sqrt(5) + sqrt(3)

Factorise: (i) 4sqrt(3)x^(2) + 5x-2sqrt(3) (ii) 7sqrt(2)x^(2)-10x - 4sqrt(2)