A man of mass 80 kg is riding on a small cart of mass 40 kg which is rolling along a level floor at a speed 2 m/s . He is running on the cart , so that his velocity relative to the cart is 3 m/s in the direction opposite to the motion of cart . What is the speed of the centre of the mass of the system ?

Consider a man sitting on the cart that is moving with initial and final velocities . Which has 4.54 m/s as the resulting change in speed of the cart?

A man of mass m is standing on the flat top of a cart of mass 2m . The length and height of the cart is L and H respectively and it is at rest on a smooth horizontal ground. The man starts running from end A, speeds up and jumps out of the cart at point B with a velocity u relative to the cart in horizontal direction. Calculate the total horizontal distance covered by the man by the time he lands on the ground.

A force F= 2t^2 is applied to the cart of mass 10 Kg, initially at rest. The speed of the cart at t = 5 s is -

A cart is moving with a velocity 20 m/s. Sand is being dropped into the cart at the rate of 50 kg/min. The force required to move the cart with constant velocity will be :

A cart is moving with a velocity 20m/s. Sand is being dropped into the cart at the rate of 50 kg/min. The force required to move the cart with constant velocity will be :-

A cart is moving with a velocity 20m/s. Sand is being dropped into the cart at the rate of 50 kg/min. The force required to move the cart with constant velocity will be :-

A cart is moving with a velocity 20m/s. Sand is being dropped into the cart at the rate of 50 kg/min. The force required to move the cart with constant velocity will be :-