A line L : y = mx + 3 meets y-axis at E (0, 3) and the arc of the parabola `y^2 = 16x` `0leyle6` at the point art `F(x_0,y_0)`. The tangent to the parabola at `F(X_0,Y_0)` intersects the y-axis at `G(0,y)`. The slope m of the line L is chosen such that the area of the triangle EFG has a local maximum P) m= Q) = Maximum area of `triangle EFG` is (R) `y_0=` (S) `y_1=`

line L:y=mx+3 meets y–axis at E(0, 3) and the are of the parabola y^(2)=16x, 0leyle6 at the point F(x_(0),y_(0)) . The tangent to the parabola at F(x_(0),y_(0)) intersects the y-axis at G(0,y_(1)) . The slope m of the L is chosen such that the area of the triangle EFG has a local maximum. Match List I with List II and select the correct answer using the code given below the lists :

The axis of the parabola y^(2)+2x=0 is

the image of the parabola y^(2)=x in the line x+y+4=0 is

The axis of the parabola y^(2)+4x+4y-3=0 is

Area bounded by the parabola x^(2)=16 y and the line x-2y=0 is

The angle between tangents to the parabola y^(2)=4ax at the points where it intersects with teine x-y-a=0 is (a>0)

If the line ax+by+c=0 is a tangent to the parabola y^(2)-4y-8x+32=0, then :