For `NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g)`, the observed, pressure for reaction mixture in equilibrium is `1.12` atm at `106^(@)C`. What is the value of `K_(p)` for the reaction?

For NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g) reaction started only with NH_(4)HS(s) , the observed pressure for reaction mixture in equilibrium is 1.2 atm at 106^(@)C . What is the value of K_(p) for the reaction?

For NH_4HS(s) hArr NH_3 (g) + H_2S , The observed pressure for reaction mixture in equillibrium is 1.12 atm at 160^Oc . Calculate the value of K_p for the reaction:

Ammonium hydrogen sulphide dissociated according to the equation, NH_4HS(s) hArr NH_3(g) +H_2S(g) . If the observed pressure of the mixture is 1.12 atm at 106^@C , what is the equilibrium constant K_p of the reactions ?

For NH_(4)HS(s)hArr NH_(3)(g)+H_(2)S(g) If K_(p)=64atm^(2) , equilibrium pressure of mixture is

For NH_(4)HS(s)hArr NH_(3)(g)+H_(2)S(g) If K_(p)=64atm^(2) , equilibrium pressure of mixture is

For NH_4HS(s)hArrNH_3(g)+H_2S(g) , if K_p = 64 atm^2 , equilibrium pressure of mixture is

NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) In the above reaction, if the pressure at equilibrium and at 300K is 100atm then what will be equilibrium constant K_(p) ?

NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) In the above reaction, if the pressure at equilibrium and at 300K is 100atm then what will be equilibrium constant K_(p) ?

NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) In the above reaction, if the pressure at equilibrium and at 300K is 100atm then what will be equilibrium constant K_(p) ?