Home
Class 12
MATHS
Find the equation of the plane contai...

Find the equation of the plane containing the lines `(x-5)/4=(y-7)/4=(z+3)/(-5)a n d(x-8)/7=(y-4)/1=(z-5)/3dot`

Text Solution

AI Generated Solution

To find the equation of the plane containing the given lines, we can follow these steps: ### Step 1: Identify the direction ratios of the lines The first line is given by the equations: \[ \frac{x-5}{4} = \frac{y-7}{4} = \frac{z+3}{-5} \] From this, we can extract the direction ratios of the first line, which are \( (4, 4, -5) \). ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of plane containing the lines (x-5)/(4)=(y+7)/(4)=(z+3)/(-5) and (x-8)/(7)=(y-4)/(1)=(z-5)/(3) .

Show that the lines (x-5)/4=(y-7)/4=(z+3)/(-5) and (x-8)/7=(y-4)/1=(z-5)/3 intersect each other

Find the equation of the plane which contains two parallel to lines (x-4)/1=(y-3)/(-4)=(z-2)/5\ a n d\ (x-3)/1=(y+2)/(-4)=z/5dot

Find the equation of the plane which contains two parallel lines given by (x-3)/1=(y+2)/-4=z/5 and (x-4)/1=(y-3)/-4=(z-2)/5

Find the equation of the plane passing through the line (x-1)/(5)=(y+2)/(6)=(z-3)/(4) and point (4,3,7)

The shortest distance between the lines (x-5)/4 = (y-7)/-5 = (z+3)/-5 and (x-8)/7 = (y-7)/1 = (z-5)/3 is

The perpendicular distance from the origin to the plane containing the two lines,(x+2)/(3)=(y-2)/(5)=(z+5)/(7) and (x-1)/(1)=(y-4)/(4)=(z+4)/(7) is: (a) 11sqrt(6)(b)(11)/(sqrt(6))(c)11(d)6sqrt(11)

Equation of the plane containing the straight line (x)/(2)=(y)/(3)=(z)/(4) and perpendicular to the plane containing the straight lines (x)/(2)=(y)/(4)=(z)/(2) and (x)/(4)=(y)/(2)=(z)/(3) is

Find the shortest distance between the lines (x-1)/2=(y-2)/4=(z-3)/7 and (x-1)/4=(y-2)/5=(z-3)/7