If the equation of base of an equilateral triangle is `2x-y=1` and the vertex is `(-1,2),` then the length of the sides of the triangle is `sqrt((20)/3)` (b) `2/(sqrt(15))` `sqrt(8/(15))` (d) `sqrt((15)/2)`

If the equation of the base of an equilateral triangle is 2x - y=1 and the vertex is (-1,2), then the length of a side of the triangle is-

If the equation of the base of an equilateral triangle is 2x - y=1 and the vertex is (-1,2), then the length of a side of the triangle is-

If the equation of base of an equilateral triangle is 2x - y = 1 and the vertex is (-1, 2), then the length of the side of the triangle is

If the equation of base of an equilateral triangle is 2x-y=1 and the vertex is (-1,2), then the length of the sides of the triangle is (a) sqrt((20)/3) (b) 2/(sqrt(15)) (c) sqrt(8/(15)) (d) sqrt((15)/2)

If the equations of base of an equilateral triangle is 2x -y =1 and the vertex is (-1,2) , then the length of the side of the triangles is : a) sqrt((20)/(3)) b) (2)/(sqrt(15)) c) sqrt((8)/(15)) d) sqrt((15)/(2))

If the equation of the base of an equilateral triangle is x+y=2 and the vertex is (2,-1) , then find the length of the side of the triangle.

The equation of base of an equilateral triangle is x+y=2 and vertex is (2, -1). Then the length of the side of the triangle equals:

The equation of the base of ann equilateral triangle is 3x-4y+15=0 and one vertex is (1,2). The length of the side is

The equation to the base of an equilateral triangle is x+y=2and its vertex is at (2,-1) . Find the length of a side of the triangle.