Th ework done in moving a body of mass `4 kg` with uniform velocity of `5 ms^(-1)` for `10` second on a surface of `mu = 0.4 is (take g= 9.8m//s^(2))`

Th work done in moving a body of mass 4 kg with uniform velocity of 5 ms^(-1) for 10 second on a surface of mu = 0.4 is (take g= 9.8m//s^(2))

Find the kinetic energy of a body of mass 1 kg moving with a uniform velocity of 10 m s^(-1)

Calculate the net force acting on a body of mass 10 kg moving with a uniform velocity of 2 m/s ?

A force of 10 kg weight acting on an object of mass for 2 s gives to it a velocity of 10 ms^(-1) . What is the mass of an object in kg ? [ g=9.8ms^(-1) ]

A particular of mass 0.6 g and having charge of 25 nC is moving horizontally with a uniform velocity 1.2xx10^(4) ms^(-1) in a uniform magnetic induction is ( g=10 ms^(-2) )

A body of mass 10 kg is moving with a velocity of 100 m/s. find the force needed to stop it in 5 seconds.

Calculate the weight of a body of mass 10 kg in newton . Take g = 9.8 "m s"^(-2) .

Calculate the weight of a body of mass 10 kg in kgf . Take g = 9.8 "m s"^(-2) .