The equation of a circle which touches the line `x +y= 5` at `N(-2,7)` and cuts the circle `x^2 + y^2 + 4x-6y + 9 = 0` orthogonally, is

Find the equation of a circle, which touches the line x+ y = 5 at the point (-2, 7) and cuts the circle x^2+ y^2+ 4x - 6y +9 =0 orthogonally.

The radius of the circle which touches the line x+y=0 at M(-1,1) and cuts the circle x^(2)+y^(2)+6x-4y+18=0 orthogonally,is

The equation of the circle which passes through the origin,center lies on the line x+y=4 and cuts the circle x^(2)+y^(2)-4x+2y+4=0 orthogonally :

The circle, which passes through the origin and whose centre lies on the line y = x and cutting the circle x^2+y^2-4x-6y+10 = 0 orthogonally is :

The locus of the centre of the circle which cuts the circles x^(2) + y^(2) + 4x - 6y + 9 = 0 " and " x^(2) + y^(2) - 5x + 4y + 2 = 0 orthogonally is

The locus of the centre of the circle which cuts the circles x^(2) + y^(2) + 4x - 6y + 9 = 0 " and " x^(2) + y^(2) - 4x + 6y + 4 = 0 orthogonally is