The density of air in atomsphere decreases with height and can be expressed by the relation.
`rho=rho_(0)e^(-Ah)`
Where `rho_(0)` is the density at sea-level, A is a constant and h is the height. Calculate the atmospheric pressure at sea -level. assume g to be constant.

The density of air in atmoshpere decreases with height and can be expressed by the relaton rho = rho_0e^(-alphah where rho_0 is the density at sea level , alpha is a constant and h is the height, Calculate the atmospheric pressure at sea level. Assume g to be constatn. The numerical values of constants are : g = 9.8 ms^-2 , rho_0 = 1.3 kg m^-3 , alpha = 1.2 xx 10^-4 m^-1

It is known that density rho of air decreases with height y (in metres) as : rho = rho_(0) e^(-y//y_0) where rho_0 = 1.25 kg m^-3 is the density at sea level and y_0 is a constant. This density variation is called the law of atmospheres. Obtain this law assuming the temperature of atomoshpere remains constant (isothermal conditions). Also assume that the value of g remains constant.

(a). It is known that density rho of air decreases with height y as rho=rho_(0)e^(-y//y(_o)) ltb rgt where p_(o)=1.25kgm^(-3) is the density at sea level, and y_(o) is a constant. This density variation is called the law of atmospheres. Obtain this law assuming that the temperature of atmosphere remains a constant (isothermal conditions). Also assume that the value of g remains constant (b). A large He balloon of volume 1425m^(3) is used to lift a payload of 400 kg. Assume that the balloon maintains constant radius as it rises. How high does it rise? [take y_(o)=8000m and rho_(He)=0.18kgm^(-3) ]

It is known that density rho of air decreases with height y as -y//y_(0) rho=rho_(o)e where rho_(o)=1.25kgm^(-3) is the density at sea level and y_(o) is a constant . This density variation is called the law of atmospheres. Obtain this law assuming that the temperature of atmosphere remains a constant (isothermal conditions).Also assume that the value of g remains constant. (b) A large He balloon of volume 1425m^(3) is used to lift a payload of 400 kg . Assume that the balloon maintains constant radius as it rises . How high does it rise ? (y_(o)=8000mandrho_(He)=0.18kgm^(-3)) .

(a). It is known that density rho of air decreases with height y as rho=rho_(0)e^(-y//y(_o)) ltb rgt where p_(o)=1.25kgm^(-3) is the density at sea level, and y_(o) is a constant. This density variation is called the law of atmospheres. Obtain this law assuming that the temperature of atmosphere remains a constant (isothermal conditions). Also assume that the value of g remains constant (b). A large He balloon of volume 1425m^(3) is used to lift a payload of 400 kg. Assume that the balloon maintains constant radius as it rises. How high does it rise? [take y_(o)=8000m and rho_(He)=0.18kgm^(-3) ]