A body falls from rest freely under gravity with an acceleration of `9.8 m//s^(2)`. Neglecting air resistance, the distance travelled by the body during the third second of its motion will be:

A body starts from rest and moves with an acceleration of 2 m//s^(2) . Find the distance covered by the body in the 10th second of its motion. [[Hint : Distance covered in the 10th second = distance covered in 10 s — distance covered in 9 s]

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.

A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be

A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be

Find the ratio of the distances travelled by a freely falling body in first, second and third second of its fall.

Find the ratio of the distances travelled by a freely falling body in first, second and third second of its fall.