`4 3/7-1 3/(14)=?+2 3/(28)` `1 3/(28)` (b) `3 1/(14)` (c) `3 3/(14)` (d) `3 1/(28)` (e) None of these

12(1)/(3)+10(5)/(6)-7(2)/(3)-1(4)/(7)=?( a) 11(13)/(14) (b) 13(11)/(14)(c)13(13)/(14) (d) 14(11)/(13) (e) None of these

1/((2 1/3))+1/((1 3/4)) is equal to (a) 7/(14) (b) (12)/(49) (c) 4 1/(12) (d) None of these

2 3/7 -2 1/4 -1 1/14 +1 1/28 =?

(1)/((2(1)/(3)))+(1)/((1(3)/(4))) is equal to (a) (7)/(14) (b) (12)/(49) (c) 4(1)/(12) (d) None of these

Solve : (3x +4)/(7) - (x +5)/(14) = (x)/(28) + (x +1)/(14) The following steps are involved in solving the above problem. Arrange them in sequential order (A) 5x + 3 = (3x + 2)/(2) rArr 10 x + 6 = 3x + 2 (B) rArr 7x = -4 (C) Given (3x + 4)/(7) - (x + 5)/(14) = (x)/(28) + (x +1)/(14) rArr (6x + 8 -x -5)/(14) = (x + 2x + 2)/(28) (D) rArr x = -(4)/(7)

Using appropriate properties find : (2)/(5) xx ((-3)/(7)) - (1)/(6) xx (3)/(2) + (1)/(14) xx (2)/(5) = (2)/(5) xx ((-3)/(7)) + (1)/(14) xx (2)/(5) - (1)/(cancel6) xx (cancel 3)/(2) = (2)/(5) xx ((-3)/(7) + (1)/(14) ) - (1)/(4) = (2)/(5) xx ((-6+1)/(14))- (1)/(4) = (cancel 2)/(cancel 5) xx (-cancel 5)/(cancel14) - (1)/(4) = (-1)/(7) - (1)/(4) (- 4 - 7)/(28) = (-11)/(28)

1-(3)/(16)+(1.4)/(1.2)((3)/(16))^2- (1.4.7)/(1.2.3)((3)/(16))^3 + …..=

(3)/(4)" of "((1)/(3)+(1)/(2))-:((1)/(7)+1(1)/(14))" of "2times(1)/(4)-(1)/(2)" of "(3)/(4)