Due to `10` ampere of current flowing in a circular coil of `10 cm` radius, the magnetic field produced at its centre is `3.14xx10^(-3) Weber//m^(3)`. The number of turns in the coil will be

Due to 10 A of current flowing in a circular coil of 10 cm radius , the magnetic field produced at its centre is 3.14xx10^-3 Wb/ m^2 . The number of turns in the coil will be

Due to 10 A of current flowing in a circular coil of 10 cm radius , the magnetic field produced at its centre is 3.14 xx 10^-3Wb//m^2 .The number of turns in the coil will be

2A current is flowing in a circular coil of 'n' turn, having 10cm radius. The flux density at its centre is 0.126 xx 10^(-2) wb//m^(2) . The value of 'n' is

A current of 2 A is made to flow through a coil which has only one turn. The magnetic field produced at the centre is 4pi xx 10^(-6) "Wb"//m^(2). the radius of the coil is

A current of 2 A is made to flow through a coil which has only one turn. The magnetic field produced at the centre is 4pi xx 10^(-6) "Wb"//m^(2). the radius of the coil is

A coil of 10 cm radius, carrying a current of 1 A produces magnetic field of induction 6.284xx10^(-3)Wb//m^(2) at its cente. What is the number of turns of the coil ?

A current of 1 A is flowing through a circular coil of radius 10 cm having N turns. If the magnetic field produced at the centre of the coil be 4pixx10^(-6)T , what is the value of N ?

At the centre of a current - carrying circular coil of radius 5 cm, magnetic field due to earth is 0.5xx10^(-5)"Wb m"^(-2) . The current flowing through the coil, so that it equals the Earth's magnetic field, is