`N` identical capacitors are connected in parallel which are charged to a potential `V`. If these are separated and connected in series then what potential difference will be obtained?

Two similar condensers are connected in parallel and are charged to a potential V. Now these are separated out and are connected in series. Then

Two similar condensers are connected in parallel and are charged to a potential V. Now these are separated out and are connected in series. Then

Six identical capacitors are joined in parallel, charged to a potential difference of 10 V, separated and then connected in series. Then the potential difference between the free plates is

Two idential capacitors are joined in parallel, charged to a potential V and then separated and then connected in series i.e. the positive plate of one is connected to negative of the other

Two idential capacitors are joined in parallel, charged to a potential V and then separated and then connected in series i.e. the positive plate of one is connected to negative of the other. Then

Two idential capacitors are joined in parallel, charged to a potential V and then separated and then connected in series i.e. the positive plate of one is connected to negative of the other

Suppose n identical capacitors are joined in parallel and charged to potential V. Now, they are separated and joined in series. If the energy possessed by each capacitor is U, then on joining them in series, the energy and potential difference for the combination are

n identical capacitors are connected in parallel to a potential difference V . These capacitors are then reconnected in series, their charges being left undisturbed. The potential difference obtained is

n identical capacitors are connected in parallel to a potential difference V . These capacitors are then reconnected in sereis, their charges being left undisturbed. The potential difference obtained is

When a parallel plate capacitor is connected to a source of constant potential difference