Find the equation of the projection of the line `(x-1)/2=(y+1)/(-1)=(z-3)/4` on the plane `x+2y+z=9.`

Find the equations of the projection of the line (x+1)/(-2)=(y-1)/(3)=(z+2)/(4) on the plane 2x+y+4z=1

The equation of the projection line of the line (x+1)/(2)=(y+1)/(-1)=(z+3)/(4) on the plane x+2y+z=6 is

Reflection of the line (x-1)/(-1)=(y-2)/(3)=(z-3)/(1) in the plane x+y+z=7 is

Point of intersection of the line (x-1)/2 = (y-2)/3 = (z+3)/4 and the plane 2x+4y -z=1 is

Equation of line of projection of the line 3x-y+2z-1=0=x+2y-z-2 on the plane 3x+2y+z=0 is:

Find the equation of the plane containing the line. : (x -1)/(2) = (y -2)/(-1) = (z - 3)/(4) and perpendicular to the plane x + 2y + z - 2 = 0 .

Find the equation of the line passing through the point P(4,6,2) and the point of intersection of the line (x-1)/(3)=(y)/(2)=(z+1)/(7) and the plane x+y-z=8 .

The point of intersection of the line (x-1)/3=(y+2)/4=(z-3)/-2 and the plane 2x-y+3z-1=0 , is