Find the equation of the ellipse whose focus is (1,-2) the directrix `3x-2y+5=0\ a n d\ ` eccentricity equal to 1/2.

Find the equation of the ellipse hose focus is (1,-2) the directrix 3quad -2quad +5=0 eccentricity equal to 1/2.

Find the equation of the ellipse whose focus is (1,0), the directrix is x+y+1=0 and eccentricity is equal to 1/sqrt(2.)

Find the equation of the ellipse whose focus is (1,0), the directrix is x+y+1=0 and eccentricity is equal to (1)/(sqrt(2))

The equation of the ellipse whose focus is (1,-1), directrix x-y-3=0 and eccentricity equals (1)/(2) is :

Find the equation of the ellipse whose focus (-1,1) e=1/2 and directrix is x-y+3=0

Find equation of the ellipse whose focus is (1,-1), then directrix the line x-y-3=0 and eccentricity 1/2 is

The equation of the ellipse whose focus is (1,0) and the directrix is x+ y+1=0 and eccentricity is equal to 1//sqrt(2) is

The equation of the ellipse whose focus is (1,-1) the directrix the line x-y-3=0 and eccentricity (1)/(2) is

Find the equation of the ellipse whose focus is (1,-2) , the corresponding directrix x-y+1=0 and eccentricity (2)/(3) .