The rate of flow of liquid ina tube of radius r, length l, whose ends are maintained at a pressure difference P is `V = (piQPr^(4))/(etal)` where `eta` is coefficient of the viscosity and Q is

The rate of flow of liquid in a tube of radius r, length l, whose ends are maintained at a pressure difference P is V = (piQPr^(4))/(etal) where eta is coefficient of the viscosity and Q is

The rate of low of liquids in a tube of radius V length l, whose ends are maintained at a pressure difference p is V = (pi Q p r^(4))/(eta l) , where eta is coefficient of viscosity & Q is

The rate flow (V) of a liquid through a pipe of radius (r ) under a pressure gradient (P//I) is given by V = (pi)/(8)(P R^4)/(I eta), Where eta is coefficient of visocity of the liquied. Check whether the formula is correct or not.

The rate of flow Q (volume of liquid flowing per unit time) through a pipe depends on radius r , length L of pipe, pressure difference p across the ends of pipe and coefficient of viscosity of liquid eta as Q prop r^(a) p^(b) eta^(c ) L^(d) , then

The rate of flow of liquid through a capillary tube of radius r is V, when the pressure difference across the two ends of the capillary is p. If pressure is increased by 3p and radius is reduced to r/2, then the rate of flow becomes

The rate of flow of a liquid through a capillary tube of radius r is under a pressure difference of P. Calculate the rate of flow when the diameter is reduced to half and the pressure difference is made 4 P?

The rate of a flow V a of liquid through a capillary under a constant pressure depends upon (i) the pressure gradient (P/l) (ii) coefficient of viscosity of the liquid eta (iii) the radius of the capillary tube r. Show dimesionally that the rate of volume of liquid flowing per sec V∝ Pr^4 /ηl

Derive an expression for the rate of flow of a liquid through a capillary tube. Assume that the rate of flow depends on i) pressure gradient (P/l) , (ii) The radius, r and (iii) the coefficient of viscosity , eta . The value of the proportionally constant k =pi/8

Derive an expression for the rate of flow of a liquid through a capillary tube. Assume that the rate of flow depends on (i) pressure gradient (p/l) , (ii) The radius, r and (iii) the coefficient of viscosity, eta . The value of the proportionality constant k = pi/8 .

Derive an expression for the rate of flow of a liquid through a capillary tube. Assume that the rate of flow depends on (i) pressure gradient (p/l) , (ii) The radius, r and (iii) the coefficient of viscosity, eta . The value of the proportionality constant k = pi/8 .