Let `S_n` denote the sum of first `n` terms of an A.P. If `S_(2n)=3S_n ,` then find the ratio `S_(3n)//S_ndot`

Let S_(n) denote the sum of first n terms of an A.P. If S_(2n) = 3S_(n) , then the ratio ( S_(3n))/( S_(n)) is equal to :

Let S_n denote the sum of the first n tem of an A.P. If S_(2n)=3S_n then prove that (S_(3n))/(S_n) =6.

Let S_(n) denote the sum of the first n tem of an A.P.If S_(2n)=3S_(n) then prove that (S_(3n))/(S_(n))=6

Let S_n denotes the sum of the first of n terms of A.P. and S_(2n)=3S_n . then the ratio S_(3n):S_n is equal to

Let S_n denote the sum of first n terms of an A.P. and S_2n = 3S_n then ratio of S_3n : S_n

Let S_(n) be the sum of first n terms of an A.P. If S_(2n) = 5s_(n) , then find the value of S_(3n) : S_(2n) .