Find the distance of the point `(-1,-5,-10)` from the point of intersection of the line `(x-2)/3=(y+1)/4=(z-2)/(12)` and plane `x-y+z=5.`

Find the distance of the points (-1, -5, -10) form the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and plane x-y+z=5

The distance of the point (-1, -5, -10) from the point of intersection of the line (x-2)/(2)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=5 is

The disatance of the point (1, 0, 2) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=16 , is

Find the points of intersection of the line (x-2)/(-3)=(y-1)/2=(z-3)/2 and the plane 2x+y-z=3 .

The distance of the point (1,1,9) from the point of intersection of the line (x-3)/1=(y-4)/2 = (z-5)/2 and plane x+y+z=17

Statement 1: A point on the line (x+2)/3=(y+1)/2=(z-3)/2 at a distance 3sqrt(2) from the point (1,2,3) lies on the lne (x+7)/5=(y+t)/4=(z-2)/1 Statement 2: If d is the distance between the point (-1,-5,-10) and the point of intersectionof the line (x-2)/3=(y+1)/4=(z-2)/12 with the plane x-y+z=5 then d=13

The point of intersection of the line (x-1)/3=(y+2)/4=(z-3)/-2 and the plane 2x-y+3z-1=0 , is